如何将十六进制字符串拆分为std :: vector？ [英] How to split a hex string into std::vector?

问题描述

给定一个十六进制 std :: string 像09e1c5f70a65ac519458e7e53f36，我怎样才能将它分成两块数字并将它们存储到 std :: vector< uint8_t> ？

Given a hex std::string like "09e1c5f70a65ac519458e7e53f36", how can I split it in chunks of two digits and store them into an std::vector<uint8_t>?

块大小，但我不知道如何将十六进制块转换为数字。这是我到目前为止。

I loop over the string in steps of the chunk size, but I don't know how to convert the hex chunk into a number. This is what I have so far.

vector<byte> vectorify(string input, int chunk = 2)
{
    vector<uint8_t> result;
    for(size_t i = 0; i < input.length(); i += chunk)
    {
        int hex = input.substr(i, chunk);
        // ...
    }
    return result;
}

推荐答案

#include <string>
#include <sstream>
#include <vector>
#include <iomanip>

int main(void)
{
    std::string in("09e1c5f70a65ac519458e7e53f36");
    size_t len = in.length();
    std::vector<uint8_t> out;
    for(size_t i = 0; i < len; i += 2) {
        std::istringstream strm(in.substr(i, 2));
        uint8_t x;
        strm >> std::hex >> x;
        out.push_back(x);
    }
    // "out" contains the solution
    return 0;
}

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