DOS命令将字符串格式化为十六进制值 [英] DOS command to format string to hex value

问题描述

是否可以使用DOS命令将字符串格式化为十六进制值？我试图从命令行传递一个十六进制值到我的程序，但它将完整的值作为一个字符串，而不是十六进制值？

Is it possible to format a string to a hex value using DOS command? I'm trying to pass a hex value to my program from command line but it takes that complete value a a string and not as hex value?

推荐答案

{0：x4}-f（ [int]999）
03e7

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