链接调用的模拟或存根 [英] mock or stub for chained call

问题描述

protected int parseExpire(CacheContext ctx) throws AttributeDefineException {
    Method targetMethod = ctx.getTargetMethod();
    CacheEnable cacheEnable = targetMethod.getAnnotation(CacheEnable.class);
    ExpireExpr cacheExpire = targetMethod.getAnnotation(ExpireExpr.class);
    // check for duplicate setting
    if (cacheEnable.expire() != CacheAttribute.DO_NOT_EXPIRE && cacheExpire != null) {
        throw new AttributeDefineException("expire are defined both in @CacheEnable and @ExpireExpr");
    }
    // expire time defined in @CacheEnable or @ExpireExpr
    return cacheEnable.expire() != CacheAttribute.DO_NOT_EXPIRE ? cacheEnable.expire() : parseExpireExpr(cacheExpire, ctx.getArgument());
}

这是要测试的方法，

Method targetMethod = ctx.getTargetMethod();
CacheEnable cacheEnable = targetMethod.getAnnotation(CacheEnable.class);

我必须模拟三个CacheContext，Method和CacheEnable。
有什么想法让测试用例更简单吗？

I have to mock three CacheContext,Method and CacheEnable. Is there any idea to make the test case much simpler?

推荐答案

Mockito 可以处理链式存根：

Foo mock = mock(Foo.class, RETURNS_DEEP_STUBS);

// note that we're stubbing a chain of methods here: getBar().getName()
when(mock.getBar().getName()).thenReturn("deep");

// note that we're chaining method calls: getBar().getName()
assertEquals("deep", mock.getBar().getName());

AFAIK，链中的第一个方法返回一个模拟，设置为返回你的值第二个链式方法调用。

AFAIK, the first method in the chain returns a mock, which is set up to return your value on the second chained method call.

Mockito的作者注意到这应该仅用于遗留代码。更好的做法是将行为推送到CacheContext中，并提供完成工作所需的任何信息。您从CacheContext中提取的信息量表明您的班级有功能羡慕 。

Mockito's authors note that this should only be used for legacy code. A better thing to do otherwise is to push the behavior into your CacheContext and provide any information it needs to do the job itself. The amount of information you're pulling from CacheContext suggests that your class has feature envy.

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