来自C ++函数的HLSL着色器 [英] HLSL shader from c++ funtion

问题描述

可以使用此功能制作HLSL(高级着色器语言)着色器吗?

缓冲区可以表示为纹理.
我有1个源纹理(缓冲区)和1个目标纹理(缓冲区).

Can you make from this function HLSL (High Level Shader Language) shader?

Buffers can be presented as texture.
I have 1 source texture (buffer) and 1 destination texture (buffer).

void stretch_memory_R8G8B8A8(int source_height,int source_width,void *source_memory,int destination_height,int destination_width,void *destination_memory)
{
    BYTE *destination_memory_BYTE = (BYTE *)destination_memory;
    BYTE *source_memory_BYTE = (BYTE *)source_memory;

    const double local_initial_value_width_0 = double(destination_width)/double(source_width);

    for(int local_height_counter_source=0;local_height_counter_source<source_height;local_height_counter_source++)
    {
        int local_check_value_height = local_height_counter_source*destination_height/source_height+1+destination_height/source_height;
        if(local_check_value_height>destination_height)
        {
            local_check_value_height = destination_height;
        }
        for(int local_height_counter_destination=local_height_counter_source*destination_height/source_height;
            local_height_counter_destination<local_check_value_height;
            local_height_counter_destination++)
        {
            for(int local_width_counter_source=0;local_width_counter_source<source_width;local_width_counter_source++)
            {
                int local_initial_value_width = local_width_counter_source*local_initial_value_width_0;
                int local_check_value_width = local_initial_value_width+1+local_initial_value_width_0;
                if(local_check_value_width>destination_width)
                {
                    local_check_value_width = destination_width;
                }
                for(int local_width_counter_destination=local_initial_value_width;
                    local_width_counter_destination<local_check_value_width;
                    local_width_counter_destination++)
                {
                    *(DWORD*)(&destination_memory_BYTE[(local_width_counter_destination+local_height_counter_destination*destination_width)<<2]) =
                        *(DWORD*)(&source_memory_BYTE[(local_width_counter_source+local_height_counter_source*source_width)<<2]);
                }
            }
        }
    }
}

推荐答案

是，但是使用了不同的方法.我所阅读的像素着色器将1个像素输入，不提供一个像素或提供一些像素输出，而您的函数可一次修改整个表面.实际的像素着色器功能将有效地执行外循环的一次迭代.和全局变量(HLSL globals)将保持循环状态，下一个绘制位置等等.

yes, but with a different approach. A pixel shader from what I have read takes 1 pixel in and provides either none or some pixels out, whereas your function modifies a whole surface at once. The actual pixel shader function would effectively do one iteration of the outer loop; and global variables ( HLSL globals ) would maintain the state of the loop, next draw position and so-forth.

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