如何在Muleosft中获取有关Dataweave异常的更多信息 [英] How to get more information about dataweave exception in muleosft

问题描述

执行m子流时，我低于dataweave异常:

I am getting below dataweave exception while executing a mule flow :

"
        INFO  2016-11-06 09:02:42,097 [[abc].HTTP_Listener_Configuration.worker.01] com.mulesoft.weave.mule.utils.MuleWeaveFactory$: MimeType was not resolved '*/*' delegating to Java.
    ERROR 2016-11-06 09:02:42,290 [[abc].HTTP_Listener_Configuration.worker.01] org.mule.exception.CatchMessagingExceptionStrategy: 
    Message               : Exception while executing: 
    "Response": {
                   ^
    Unexpected character '\u000a' at index 25 (line 2, position 24), expected '"'
    Payload               : test
    Payload Type          : java.lang.String
    Element               : /Process11/processors/9/1/9 @ abc:def.xml:331 (TM_F1)
    Element XML           : <dw:transform-message doc:name="TM_F1">
                    <dw:set-payload>%dw 1.0%output application/json---{Data: [{//       in_id : flowVars.instanceId,pd: '{AmIds:[{AmId:' ++ flowVars.AmId ++ '}]}'}]}</dw:set-payload>
                    </dw:transform-message>
    Root Exception stack trace:
    com.mulesoft.weave.reader.json.JsonReaderException: Unexpected character '\u000a' at index 25 (line 2, position 24), expected '"'
    at com.mulesoft.weave.reader.json.JsonTokenizer.fail(JsonTokenizer.scala:193)
    at com.mulesoft.weave.reader.json.JsonTokenizer.require(JsonTokenizer.scala:190)
    at com.mulesoft.weave.reader.json.JsonTokenizer.readString(JsonTokenizer.scala:80)
"

是否有可能启用更多的调试选项来获取有关此特定异常的更多信息，以便于找出根本原因.

Is there any possibility to enable more debug options to get more information about this particular exception so that it will be easy to find out the root cause.

这里的问题是，即使我没有在转换消息中使用有效负载，但由于muleflow中先前的http调用返回的有效负载，我还是报错了.

The problem here is, even though i am not using the payload in transform message i am getting error because of the payload returned by the previous http call in muleflow.

M子的版本是:Studio 6.1和运行时3.8.

Mule version is : studio 6.1 and runtime 3.8.

请帮助我解决此问题.

谢谢 sdg

推荐答案

这不是dataweave问题.异常来自JsonReaderException:

This is not dataweave question. Exception what you have is from JsonReaderException:

com.mulesoft.weave.reader.json.JsonReaderException: Unexpected character '\u000a' at index 25 (line 2, position 24), expected '"'

这意味着您提供的JSON在第2行的位置设置了新行(\ u000a)，我想这是这样的:

It means that JSON what you provide has new line (\u000a) ate line 2 position 24. I imagine it is something like this:

"Response": {
  "Message" : "67890123
                       456 the end"
}

使用特殊字符表示JSON中的新行.

Use special characters to represent new line in JSON.

"Response": {
  "Message" : "67890123\n456 the end"
}

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