将矩阵从右手坐标系更改为左手坐标系 [英] Changing a matrix from right-handed to left-handed coordinate system

问题描述

我想从右手系统更改 4x4 矩阵，其中:
x为左右，y为前后，z为上下

I would like to change a 4x4 matrix from a right handed system where:
x is left and right, y is front and back and z is up and down

到左手系统，其中:
x 左右，z 前后，y 上下.

to a left-handed system where:
x is left and right, z is front and back and y is up and down.

对于向量来说很容易，只需交换 y 和 z 值，但是对于矩阵如何做呢?

For a vector it's easy, just swap the y and z values, but how do you do it for a matrix?

推荐答案

让我试着更好地解释一下.我需要将 z 轴朝上的 Blender 模型导出到 y 轴朝上的 OpenGL 中.

Let me try to explain it a little better. I need to export a model from Blender, in which the z axis faces up, into OpenGL, where the y axis faces up.

对于每个坐标 (x, y, z) 都很简单；只需交换 y 和 z 值:(x, z, y).
因为我已经交换了所有的 y 和 z 值，所以我使用的任何矩阵也需要翻转，以便具有相同的效果.

For every coordinate (x, y, z) it's simple; just swap the y and z values: (x, z, y).
Because I have swapped the all the y and z values, any matrix that I use also needs to be flipped so that it has the same effect.

经过大量搜索，我最终在 gamedev:

After a lot of searching I've eventually found a solution at gamedev:

如果你的矩阵是这样的:

If your matrix looks like this:

{ rx, ry, rz, 0 }  
{ ux, uy, uz, 0 }  
{ lx, ly, lz, 0 }  
{ px, py, pz, 1 }

要从左到右或从右到左改变它，像这样翻转它:

To change it from left to right or right to left, flip it like this:

{ rx, rz, ry, 0 }  
{ lx, lz, ly, 0 }  
{ ux, uz, uy, 0 }  
{ px, pz, py, 1 }

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