如何传递一个std :: string到glShaderSource？ [英] How to pass an std::string to glShaderSource?

问题描述

我有以下代码：

glShaderSource(shader, 1, (const char **)data.c_str(), NULL);

但它使我的程序崩溃。如何将 std :: string 转换为 const char ** ？
我也试过了（const char **）& 但它说需要l值，我不明白。当我使用这个代码时，它工作正常：

But it makes my program crash. How do I convert std::string into const char ** ? I also tried (const char **)& but it said "requires l-value" which I don't understand. It works fine when I use this code:

const char *data = "some code";
glShaderSource(shader, 1, &data, NULL);

但是我不能直接从 std :: string 。我可以为它分配一个新的 char 数组，但这不是很好的代码。

But I can't make it work directly from a std::string. I could allocate a new char array for it but that is not nice code.

c $ c> const GLchar 但显然没有区别。

I also tried with const GLchar but obviously it makes no difference.

推荐答案

data.c_str（）返回 const char * ，所以这样做：

const char *c_str = data.c_str();
glShaderSource(shader, 1, &c_str, NULL);

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