编写一个C程序来模仿一个2位半加法器 [英] Write a C program to imitate a 2-bit half adder

问题描述

在C编程中模仿2位半加法器的代码



我尝试过：



#include< stdio.h>



typedef char bit;

bit carry = 0;

位halfadd（位A，位B）{

carry = A& B;

返回A ^ B;

}

code to imitate a 2-bit half adder in C programming

What I have tried:

#include<stdio.h>

typedef char bit;
bit carry = 0;
bit halfadd( bit A, bit B ){
carry = A & B;
return A ^ B;
}

推荐答案

现在您需要做的就是添加代码调用你的函数！

Now all you need to do is add the code to call your function!

int main()
{
    for (int i = 0; i < 2; i++)
    {
        for (int j = 0; j < 2; j++)
        {
            int result = halfadd(i, j);
            printf("%d + %d = %d:%d\n", i, j, result, carry);
        }
    }
    return 0;
}

虽然说实话，您可能希望在计算中包含任何现有的进位...

Though to be honest, you might want to include any existing carry in your calculation...

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