设置许可证的Linux内核模块 [英] Setting the license for modules in the linux kernel

问题描述

我已经写在阿达一些内核模块，我已经打了一个有点问题。许可证被定义为一个C宏，我想不通，它实际上是什么。它是一个合适的解决方案，只是有一些C再出口需要GPL如果这两个c和ADA模块有GPL兼容许可证的所有C函数？有没有更好的方式来做到这一点？

I've written some kernel modules in Ada, and I've hit a bit of a problem. License is defined as a c macro, and I can't work out what it actually is. Is it a suitable solution to simply have some c re-exporting all the c functions which require GPL if both the c and the ada module have GPL compatible licenses? Is there a better way to do this?

推荐答案

与C宏处理是皇室PITA。我有一个梦想，有一天C程序员会做世界青睐的休息和使用他们戒烟。

Dealing with C macros is a royal PITA. I have a dream that one day C programmers will do the rest of the world a favor and quit using them.

如果是我的话，我会运行宏来看看它的输出，然后写一些阿达code输出等价的。

If it were me, I'd run the macro to see what it outputs, then write some Ada code to output the equivalent.

从通过Roland的答案读，它看起来对我来说，实现定义编译linker_section 可能需要

From reading through Roland's answer, it looks to me like the implementation-defined pragma linker_section may be required.

编译Linker_Section（[实体=>] LOCAL_NAME，[科=>]
  static_string_EX preSSION）;

pragma Linker_Section ( [Entity =>] LOCAL_NAME, [Section =>] static_string_EXPRESSION);

LOCAL_NAME必须指被在库中声明的对象
  水平。该编译指定的连接器部分的名称
  给定的实体。它等同于 __在GNU C属性__（（部分））
  并导致LOCAL_NAME被放置在static_string_EX preSSION
  可执行文件的部分（假设链接器不重命名
  部分）。

LOCAL_NAME must refer to an object that is declared at the library level. This pragma specifies the name of the linker section for the given entity. It is equivalent to __attribute__((section)) in GNU C and causes LOCAL_NAME to be placed in the static_string_EXPRESSION section of the executable (assuming the linker doesn't rename the section).

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